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2 years ago

If you were to take a trip around the surface of one of the planets,

1 answer:

7 0

The time taken to take a trip around a planet depends on its size. Since Venus has almost the same size as the earth, it would take you about the same amount of time to take a trip round Venus as a trip around the Earth.

The solar system is composed of the planets; Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, Neptune, Pluto.

All these planets move round the sun in their orbits. The planets vary in size.

However, Venus(7,926 miles) has almost the same size as the earth(7,521 miles).

The period of Venus is 243 earth days while the period of the earth is 365 earth days.

Hence, it would take you about the same amount of time to take a trip round Venus as a trip around the Earth.

Learn more: brainly.com/question/12075871

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An excited ozone molecule, O3*, in the atmosphere can undergo one of the following reactions,O3* → O3 (1) fluorescenceO3* → O +

Maurinko [17]

Answer:

The simplified expression for the fraction is $\text {X} = \dfrac{ {k_3 \times cM} }{k_1 +k_2 + k_3 }$

Explanation:

From the given information:

O3* → O3 (1) fluorescence

O + O2 (2) decomposition

O3* + M → O3 + M (3) deactivation

The rate of fluorescence = rate of constant (k₁) × Concentration of reactant (cO)

The rate of decomposition is = k₂ × cO

The rate of deactivation = k₃ × cO × cM

where cM is the concentration of the inert molecule

The fraction (X) of ozone molecules undergoing deactivation in terms of the rate constants can be expressed by using the formula:

$\text {X} = \dfrac{ \text {rate of deactivation} }{ \text {(rate of fluorescence) +(rate of decomposition) + (rate of deactivation) } } }$

$\text {X} = \dfrac{ {k_3 \times cO \times cM} }{ {(k_1 \times cO) +(k_2 \times cO) + (k_3 \times cO \times cM) } }$

$\text {X} = \dfrac{ {k_3 \times cO \times cM} }{cO (k_1 +k_2 + k_3 \times cM) }$

$\text {X} = \dfrac{ {k_3 \times cM} }{k_1 +k_2 + k_3 }$ since cM is the concentration of the inert molecule

7 0

2 years ago

The second-order diffraction for a gold crystal is at an angle of 22.20o for X-rays of 154 pm. What is the spacing between the c

Alenkinab [10]

<u>Answer:</u> The spacing between the crystal planes is $4.07\times 10^{-10}m$

<u>Explanation:</u>

To calculate the spacing between the crystal planes, we use the equation given by Bragg, which is:

$n\lambda =2d\sin \theta$

where,

n = order of diffraction = 2

$\lambda$ = wavelength of the light = $154pm=1.54\times 10^{-10}m$ (Conversion factor: $1m=10^{12}pm$ )

d = spacing between the crystal planes = ?

$\theta$ = angle of diffraction = 22.20°

Putting values in above equation, we get:

$2\times 1.54\times 10^{-10}=2d\sin (22.20)\\\\d=\frac{2\times 1.54\times 10^{-10}}{2\times \sin (22.20)}\\\\d=4.07\times 10^{-10}m$

Hence, the spacing between the crystal planes is $4.07\times 10^{-10}m$

4 0

2 years ago

A helium-filled weather balloon has a volume of 512 L at 18.9°C and 756 mmHg. It is released and rises to an altitude of 2.14 km

vazorg [7]

633.97 L

Explanation:

Well use the combined gas law;

P₁V₁T₁ = P₂V₂T₂

We need to change the temperatures into Kelvin;

18.9°C= 292.05 K

5.9°C = 279.05 K

756 * 512 * 292.05 = 639 * V₂ * 279.05

113,044,377.6 = 178,312.95 V₂

V₂ = 113,044,377.6 / 178,312.95

V₂ = 633.97 L

3 0

2 years ago

Read 2 more answers

given the diagram below which contains a mixture of three acids in an aqueous solution, identify the color of the sphere that re

charle [14.2K]

The acid having the yellow anion is a weak acid.

The weak acid is the acid that does not dissociate completely in solution. Strong acids are known to dissociate completely in solution. Hence, their cations and anions do not occur together in solution.

Weak acids acids do not dissociate in solution hence, we can still spot the cations connected to their anions in solution. Hence, the acid having the yellow anion is a weak acid.

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7 0

1 year ago

Which process of the water cycle occur by releasing energy?

pshichka [43]

Condensation occurs through the release of energy

5 0

2 years ago