All categories

2 years ago

PLEASE HELP!

Physics

1 answer:

sergiy2304 [10]2 years ago

6 0

Answer: b

Explanation:

p=mv

p=30

m=1500

rearrange to find v

(30)=(1500)(v)

v= 30/1500

v = 0.02 m/s

You might be interested in

The ratio of yellow bottles to green bottles is 3:7. If I have 50 bottles how many are yellow

azamat

15 yellow bottles.

3 + 7 = 10
50 / 10 = 5
3 x 5 = 15

7 0

2 years ago

An automobile tire having a temperature of −1.5 ◦C (a cold tire on a cold day) is filled to a gauge pressure of 26 lb/in2 . What

Salsk061 [2.6K]

Answer: $32.22\ lb/in^2$

Explanation:

Given

Temperature on the hot day $T_i=-1.5^{\circ} C\approx 271.5\ K$

Gauge Pressure $P_i=26\ lb/in^2$

When Temperature rises to $T_f=40^{\circ}C\approx 313\ K$ on a hot day then

absolute pressure is let say $P_f$

Using ideal gas equation we can write

$\Rightarrow \frac{PV}{T}=constant$

as volume is constant therefore

$\Rightarrow \frac{P}{T}=constant$

$\Rightarrow \frac{26+14.7}{271.5}=\frac{P_f}{313}$

$\Rightarrow P_f=46.92\ lb/in^2$

Gauge Pressure is given by

$\Rightarrow 46.92-14.7=32.22\ lb/in^2$

6 0

2 years ago

What amount of force is needed to propel and object of 27 kg to an acceleration of 11,550 m/s^2? (1 point)

aliya0001 [1]

Answer:

311,850 N

Explanation:

We can solve the problem by using Newton's second law:

$F=ma$

where

F is the net force applied on an object

m is the mass of the object

a is its acceleration

For the object in this problem,

m = 27 kg

$a=11550 m/s^2$

Substituting, we find the force required:

$F=(27)(11550)=311,850 N$

3 0

2 years ago

The Bohr radius a0 is the most probable distance between the proton and the electron in the Hydrogen atom, when the Hydrogen ato

katen-ka-za [31]

Answer:

The electric force is $F = 11.9 *10^{-9} \ N$

Explanation:

From the question we are told that

The Bohr radius at ground state is $a_o = 0.529 A = 0.529 ^10^{-10} \ m$

The values of the distance between the proton and an electron $z = 2.63a_o$

The electric force is mathematically represented as

$F = \frac{k * n * p }{r^2}$

Where n and p are charges on a single electron and on a single proton which is mathematically represented as

$n = p = 1.60 * 10^{-19} \ C$

and k is the coulomb's constant with a value

$k =9*10^{9} \ kg\cdot m^3\cdot s^{-4}\cdot A^2.$

substituting values

$F = \frac{9*10^{9} * [(1.60*10^{-19} ]^2)}{(2.63 * 0.529 * 10^{-10})^2}$

$F = 11.9 *10^{-9} \ N$

3 0

2 years ago

Which graph shows acceleration? A graph of position (meters) versus time (seconds) has a straight line running from 0 seconds 0

charle [14.2K]

It's the one that has a concave line running upward.

6 0

2 years ago

Read 2 more answers