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9 months ago

A solid weighs 0.9N in air and 0.2N in a liquid of density 700kg/m^3. Calculate

Physics

1 answer:

Setler [38]9 months ago

7 0

The correct answer is Upthrust= 0.7N and Volume = 1.02 x 10⁻² g

Solid weighs.09 N in air.

Solid weighs less than liquid because of an upward force operating on it (solid weighs in liquid =.02 N).

A solid body experiences an upthrust when it is partially or entirely submerged in a fluid, such as water. In this case, the fluid's weight (water) equals the fluid's weight that the water has displaced.

upthrust is = to.09 -.02 N = 0.7N.

Upthrust = displaced liquid's weight

so that weight of liquid equal to volume of solid = 0.7 N

Volume of solid times mass of liquid = 0.07/9.8 = 0.00714 = 7.14 x 10⁻³ kg

Volume = Mass / density

Volume = 7.14 x 10⁻³ / 700

= 1.02 x 10⁻⁵ kg= 1.02 x 10⁻² g

To learn more about upthrust refer the link:

brainly.com/question/24383048

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2 years ago

Read 2 more answers

An object that weighs 2.450 N is attached to an ideal massless spring and undergoes simple harmonic oscillations with a period o

Viktor [21]

Answer:

Spring constant, k = 24.1 N/m

Explanation:

Given that,

Weight of the object, W = 2.45 N

Time period of oscillation of simple harmonic motion, T = 0.64 s

To find,

Spring constant of the spring.

Solution,

In case of simple harmonic motion, the time period of oscillation is given by :

$T=2\pi\sqrt{\dfrac{m}{k}}$

m is the mass of object

$m=\dfrac{W}{g}$

$m=\dfrac{2.45}{9.8}$

m = 0.25 kg

$k=\dfrac{4\pi^2m}{T^2}$

$k=\dfrac{4\pi^2\times 0.25}{(0.64)^2}$

k = 24.09 N/m

k = 24.11 N/m

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6 0

2 years ago

If the period of a spring is 5 seconds what is the frequency

Scilla [17]

Answer:

C. 0.2 Hertz

Explanation:

The frequency of a spring is equal to the reciprocal of the period:

$f=\frac{1}{T}$

where

f is the frequency

T is the period

For the spring in this problem,

T = 5 s

therefore, the frequency is

$f=\frac{1}{5 s}=0.2 Hz$

7 0

2 years ago

The speed of sound is measured to be 340 m/s on a certain day.

ziro4ka [17]

Answer: 1,224 km/h

Explanation:

To do this, we pick the first unit and convert
Picking m first and converting to km:
Since we're converting from a non-prefix to a prefix, we divide the value by the prefix were taking it to. In this case, kilo = 10³ which means we're going to divide our value by 1000 to convert it from m to km
340 m/s ÷ 1000 = 0.34 km/s
Now, let's convert our seconds to hour:
We'll need to calculate how many hours is equivalent to one second first;
1 hr = 60×60 seconds
X hr = 1 second
*Cross multiply*
1 × 1 = X × 60 × 60
1 = 3,600 X
X = 1 / 3,600
X = 2.778×10⁻⁴ hour
So, in the place of "1 Second", we're going to be inserting 2.778×10⁻⁴ hour instead
0.34 km / s = 0.34 km / 2.778×10⁻⁴ hour
(0.34 / 2.778×10⁻⁴) km/hour
1,224 km/h.
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1 year ago

A beam of protons is directed in a straight line along the +z direction through a region of space in which there are crossed ele

IceJOKER [234]

Answer:

B = 7.6 T direction of + x

Explanation:

For the proton beam to continue in the same direction the electric and magnetic forces must be equal

$F_{m} - F_{e}$ = 0

$F_{m}$ = F_{e}

Fm = q E

The electric force is in the direction of the electric field because it is the charge of the positive proton, the electric force goes in the direction of –y, therefore, the magnetic force cancels this force must go in the direction of + y

The magnetic force is

F_{m} = q v x B = q v B sin θ

θ = 90

B = q E / q v

B = E / v

B = 800/105

B = 7.6 T

To find the direction of the magnetic field we use the right hand rule, the thumb goes in the direction of the proton velocity, the fingers extended in the direction of the magnetic field and the palm is the direction of force, for a positive charge.

Thumb goes in the direction of the + z axis

Palm in the direction of +y

Fingers point in the direction of + x

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2 years ago