Answer my math question I asked so many times I lost most of points by

Mathematics

1 answer:

kumpel [21]2 years ago

8 0

Answer:

i think ur in a higher grade then me but im good w/ equations so OoOO0p

Step-by-step explanation:

equation: y = x - 6 + x^2

(6,0) (7,1) (8,4) (9,9)

I figured this out by looking at the point (6,0). To get 0 (y), you have to subtract 6. Knowing this, I subtracted 6 from the rest of the coordinates, leaving me with numbers that are able to be squared to get y. This led me to the equation x - 6 + x^2.

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If f(x) = -x-2, what is f¹(x)?

astra-53 [7]

Answer:

f¯¹(x) =9x+18, for the pictorial(image) question
what is the send question is it asking derivative or inverse
If it is inverse f¯¹(x)=-x-2 as it is
Or if it is derivative f'(x)=-1

Step-by-step explanation:

<h2>For the image question f(x)=1/9x-2,f¯¹(x)=?</h2>

f(x)=1/9x-2............given
y=1/9x-2................swapping f(x) by y to Easily write
x=1/9y-2................interchanging x and y
1/9y-2=x................changeling side of equation
9(1/9y-2)=(x)9.......multiplying both sides by 9 to override the fraction on the right side
y-18=9x
y=9x-18.................Return to where it were
f¯¹(x)=9x+18..........swap back f¯¹(x) in the y

<h2>For the question f(x)=-x-2,f¯¹(x)=?</h2>

following the ☝️ arrangement
y=-x-2
x=-y-2
-y-2=x
-y=x+2
y=-x-2
f¯¹(x)=-x-2

4 0

1 year ago

Pleasantburg has a population growth model of P(t)=at2+bt+P0 where P0 is the initial population. Suppose that the future populat

Salsk061 [2.6K]

Answer: In June 2097

Step-by-step explanation:

According to the model, to find how many years t should take for $P(t)=21100$ we must solve the equation $0.9t^2+6t+14000=21100$ . Substracting 21100 from both sides, this equation is equivalent to $0.9t^2+6t-7100=0$ .

Using the quadratic formula, the solutions are $t_1= \frac{-6-\sqrt{6^2 -4*0.9*(-7100)}}{2*0.9}=-92.21$ and $t_2=\frac{-6+\sqrt{6^2 -4*0.9*(-7100)}}{2*0.9}=85.54$ . The solution $t_1=-92.21$ can be neglected as the time t is a nonnegative number, therefore $t=t_2=85.54$ .

The value of t is approximately 85 and a half years and the initial time of this model is the January 1, 2012. Adding 85 years to the initial time gives the date January 2097, and finally adding the remaining half year (six months) we conclude that the date is June 2097.

6 0

2 years ago

2.3 to 1 significant figure

azamat

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Hi there!

~

2.3 to 1 significant figure.

= 2

❀Hope this helped you!❀

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3 0