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2 years ago

Which function describes the arithmetic sequence shown?

Mathematics

1 answer:

Vedmedyk [2.9K]2 years ago

5 0

Answer:

Step-by-step explanation:

The n th term of an arithmetic sequence in functional notation is

f(x) = a₁ + (x - 1)d

where a₁ is the first term and d the common difference

d = - 7 - (- 5) = - 7 + 5 = - 2 and a₁ = - 5, thus

f(x) = - 5 - 2(x - 1) = - 5 - 2x + 2 = - 2x - 3 → D

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What is the value of 2/3(x -6) -y , when x= 9 and y=5/6?

ANTONII [103]

Answer:

Ã=7/6

Step-by-step explanation:

<h3><em>put the value of x= 9 and y=5/6 </em></h3>

=2/3(9-6)-5/6

=2/3×3-5/6

=2/1-5/6

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<em>hey mate hope it's help you</em>......

7 0

1 year ago

Read 2 more answers

4(3x^2y^4)^3 / (2x^3y^5)^4

tatyana61 [14]

Solving the expressions $\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$ we get $\frac{27}{4x^{6}y^{8}}$

Step-by-step explanation:

We need to Solve the expression: $\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$

Solving:

$\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$

$=\frac{4(3^3x^6y^{12})}{(2^4x^{12}y^{20})}\\=\frac{4(27x^6y^{12})}{(16x^{12}y^{20})}\\=\frac{108x^6y^{12}}{16x^{12}y^{20}}$

Applying exponent rule: $\frac{x^a}{x^b}=x^{a-b}$

$=\frac{108x^{6-12}y^{12-20}}{16}\\=\frac{27x^{-6}y^{-8}}{4}$

Another exponent rule says: $x^{-a}=\frac{1}{x^a}=$

$=\frac{27}{4x^{6}y^{8}}$

So, solving the expressions $\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$ we get $\frac{27}{4x^{6}y^{8}}$

Keywords: Solving Exponents

Learn more about Solving Exponents at:

#learnwithBrainly

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shusha [124]

Answer:

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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