0.25q + 0.1d = 4.95
d = 3q
0.25q + 0.1(3q) = 4.95
0.25q + 0.3q = 4.95
<u>0.55q</u> = <u>4.95</u>
0.55 0.55
q = 9
0.25(9) + 0.1d = 4.95
2.25 + 0.1d = 4.95
<u>- 2.25 - 2.25</u>
<u>0.1d</u> = <u>2.7</u>
0.1 0.1
d = 27
240 because 2000x0.04=80 X3= 240
This can solved graphically, using algebraic manipulation or differential calculus.
Plotting the equation will generate a parabola. The vertex represents the point where the ball will reach the maximum height.
The vertex can be determined by completing the square
h = -16t2 + 45t + 5
h - 5 = -16(t2 - 45/16t)
h - 5 - 2025/64 = -16(t2 - 45/16t + 2025/1024)
(-1/16)(h - 2345/64) = (t - 45/32)^2
The vertex is
(45/32,2345/64) or (1.41,36.64)
The maximum height is 36.64 ft
Using calculus, taking the first derivative of the equation and equating to 0
dh/dt = 0 = -32t + 45
t = 45/32
Substituting this value to the equation
h = -16(45/32)^2 + 45(45/32) + 5
h = 36.64 ft
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Answer:
15, 120
Step-by-step explanation:
9P4
.............................................................................................
Answer:
1.23 meters
Step-by-step explanation:
divide it by 100..
123/ 100 = 1.23 m
