Answer:
0.00840
Explanation:
The computation of the mole fraction is as follow:
As we know that
Molar mass = Number of grams ÷ number of moles
Or
number of moles = Number of grams ÷ molar mass
Given that
Number of moles of CaI2 = 0.400
And, Molar mass of water = 18.0 g/mol
Now Number of moles of water is
= 850.0 g ÷ 18.0 g/mol
= 47.22 mol
And, Total number of moles is
= 0.400 + 47.22
= 47.62
So, Molar fraction of CaI2 is
= 0.400 ÷ 47.62
= 0.00840
Answer:
4.1 moles of FeCl₃
Explanation:
The reaction expression is given as shown below:
2Fe + 3Cl₂ → 2FeCl₃
Number of moles of Cl₂ = 6.1moles
So;
We know that from the balanced reaction expression:
3 moles of Cl₂ will produce 2 moles of FeCl₃
Therefore 6.1moles of Cl₂ will produce = 4.1 moles of FeCl₃
The number of moles is 4.1 moles of FeCl₃
The illustration would be that of a double replacement reaction.
<h3>What are double replacement reactions?</h3>
They are reactions in which 2 ionic compounds exchange ions to form two new products.
Thus, in the reaction: ab + cd ----------> ad + cb
ab and cd are two ionic compounds. The b in ab is replaced by the d in cd while the d in cd itself is replaced by the b in ab. Hence, new products, ad and cd, are formed.
More on double replacement reactions can be found here: brainly.com/question/19267538
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<u>Answer:</u> The number of moles of weak acid is moles.
<u>Explanation:</u>
To calculate the moles of KOH, we use the equation:
We are given:
Volume of solution = 43.81 mL = 0.04381 L (Conversion factor: 1L = 1000 mL)
Molarity of the solution = 0.0969 moles/ L
Putting values in above equation, we get:
The chemical reaction of weak monoprotic acid and KOH follows the equation:
By Stoichiometry of the reaction:
1 mole of KOH reacts with 1 mole of weak monoprotic acid.
So, of KOH will react with = of weak monoprotic acid.
Hence, the number of moles of weak acid is moles.