Answer:
Explanation:
This is a bond with reacts with metal's
Answer:
36.8 L
Explanation:
We'll begin by converting 80 °C to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
T(°C) = 80 °C
T(K) = 80 + 273
T(K) = 353 K
Finally, we shall determine the volume occupied by the helium gas. This can be obtained as follow:
Number of mole (n) = 1.27 moles
Temperature (T) = 353 K
Pressure (P) = 1 atm
Gas constant (R) = 0.0821 atm.L/Kmol
Volume (V) =?
PV = nRT
1 × V = 1.27 × 0.0821 × 353
V = 36.8 L
Thus, the volume occupied by the helium gas is 36.8 L
Answer:
52.0004 grams of mass of potassium superoxide is required
Explanation:
Let moles carbon dioxide gas be n at 22.0 °C and 767 mm Hg occupying 8.90 L of volume.
Pressure of the gas,P = 767 mm Hg = 0.9971 atm
Temperature of the gas,T = 22.0 °C = 295.15 K
Using an ideal gas equation to calculate the number of moles.
n = 0.3662 mol
According to reaction, 2 moles of carbon-dioxide reacts with 4 moles of potassium superoxide.
Then 0.3662 mol of of carbon-dioxide will react with:
of potassium superoxide.
Mass of 0.7324 mol potassium superoxide:
0.7324 mol × 71 g/mol = 52.0004 g
52.0004 grams of mass of potassium superoxide is required.
1.3 kJ/kg K x 5 kg x 200C = 1300 kJ
The answer is <span>1,314,718 J</span>
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