How much heat energy is required to raise the temperature of 5 kilograms of coal from 20c to 220c?
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In the problem, we are tasked to solved for the amount of carbon (C) in the acetone having a molecular formula of C 3 H 6 O. We need to find first the molecular weight if Carbon (C), Hydrogen (H), Oxygen (O).
Molecular Weight:
C=12 g/mol
H=1 g/mol
O=16 g/mol
To calculate for the percent by mass of acetone, we assume 1 mol of acetone.
%C=
%C=62.07%
Therefore, the percent by mass of carbon in acetone is 62.07%
Molecular Weight:
C=12 g/mol
H=1 g/mol
O=16 g/mol
To calculate for the percent by mass of acetone, we assume 1 mol of acetone.
%C=
%C=62.07%
Therefore, the percent by mass of carbon in acetone is 62.07%
The energy transferred on the object is 1000 Joules.
Given:
An object on which a constant force of 100 N was applied to displace it over a distance of 10 meters.
To find:
The energy transfer occurs on the object.
Solution
The force applied on the object = F = 100 N
The displacement of the object = d = 10 m
The energy transferred on the object or work done is given by:
The energy transferred on the object is 1000 Joules.
Learn more about work done here: