Answer:
Lithium loses one electron to fluorine and forms ionic bond, having formula 
.
Explanation:
Lithium is the element of the group 1 and period 2 which means that the valence electronic configuration is ![[He]2s^1](https://tex.z-dn.net/?f=%5BHe%5D2s%5E1)
.
Fluorine is the element of the group 17 and period 2 which means that the valence electronic configuration is ![[He]2s^22p^5](https://tex.z-dn.net/?f=%5BHe%5D2s%5E22p%5E5)
.
<u>Thus, lithium loses 1 electron and become positively charged. Fluorine on the other hand accepts this electron and become negatively charged.</u> This is done in order that the octet of the atoms are complete. <u>These both ions then form ionic bond as their will be electrostatic interaction between the two oppositely charged ions.</u>
Thus, the formula of calcium chloride is .
Scientific investigations that involve some kind of testing will make use of observations. Generally speaking, making observations is the first step of the scientific method. Based on those observations, a question is asked, and then a hypothesis and prediction will be stated. A scientist will set up a test, observe the outcome, and collect data on the test. That will lead the scientist to some kind of conclusion relating to the initial question and hypothesis....
Answer:
Explanation:
The density formula is:
Rearrange this formula for v, volume. Multiply by v, then divide by d.
Volume can be found by dividing the mass by the density. The mass of the aluminum is 45.6 grams and the density is 2.1 grams per milliliter.
Divide. Note the grams, or g, will cancel out.
The volume of the aluminum is 21.7142857 milliliters.
The temperature of the gas sample is 813 K.
<u>Explanation:</u>
We have to use the ideal gas equation to find the temperature of the gas sample.
The ideal gas equation is PV = nRT
Pressure, P = 429 mm Hg = 0.56 atm
Volume, V = 560 mL = 0.56 L
R = gas constant = 0.08205 L atm mol⁻¹K⁻¹
Mass = 0.211 g
Molar mass of carbon di oxide = 44.01 g / mol
Moles, n = 
= 0.0047 mol
Now, we have to plugin the above values in the above equation, we will get the temperature as,
T = 
= 813 K
So the temperature of the gas sample is 813 K.
Answer:
I can't see any attachment....
