A 4.00-gram sample of sodium chloride was added to a beaker containing 40.0 mL 0.033 M lead(II)
1 answer:
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Answer:
Substance is Aluminium
Explanation:
We are given;
Mass; m = 13.5 grams
Volume; V = 5 cm³
Formula for density is;
density = m/V
Density = 13.5/5
Density = 2.7 g/cm³
From the table attached, we can see that the element with a corresponding density of 2.7 is Aluminium
