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2 years ago

Brahmagupta's book is the oldest text representing zero

Mathematics

2 answers:

Umnica [9.8K]2 years ago

7 0

Sample Answer from Edge2020.

Understanding zero as a number represented by the symbol 0 enabled mathematicians to have a representation of nothing. Having a digit to represent zero enables mathematics to be more abstract, and allows more complex problems to be solved.

Andreas93 [3]2 years ago

3 0

Answer:

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Write an equation in point-slope form for the line that passes through the point with the given slope. (–7, 6), m = 0

Nitella [24]

Answer:

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Explanation:

The point-slope formula states:

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Where

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Substituting the values from the equation gives:

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2 years ago

Find the mode of the data.

mixer [17]

The mode is a term that is repeated the most.
And the one which is the repeated is 30.

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2 years ago

Solve the equation. 2(3z-2)+8=34 A. z=3 B. z=-3 C. z=-4 D. z=5

levacccp [35]

2(3z-2)+8=34
6z - 4 + 8 = 34
6z + 4 = 34
6z = 34 -4
6z = 30
z =30/6
z = 5

answer D. z=5

6 0

2 years ago

Read 2 more answers

X²+7x+10=0 a=1, b=7, c=10 b²-4ac=(7)²-4(1) (10) =49-4(10) =49-40 =9

Sloan [31]

Answer:

X=5

X=2

Step-by-step explanation:

8 0

2 years ago

the density of a certain material is such that weighs 6900 grams for every 4.5 quarts of volume express this density in pounds p

dlinn [17]

Answer:

$d=101.4\ \text{pounds}/\text{feet}^3$

Step-by-step explanation:

Given that,

Mass of material, m = 6900 grams

Volume of the material, V = 4.5 quarts

We need to find the density in pounds per cubic foot

We know that,

1 pound = 453.59 grams

⇒ 6900 grams = 15.21 pounds

Also, 1 cubic foot = 29.92 quarts

4.5 quart = 0.15 feet³

Density = mass/volume

$d=\dfrac{15.21\ \text{pounds}}{0.15\ \text{feet}^3}\\\\d=101.4\ \text{pounds}/\text{feet}^3$

Hence, the density of the material is $101.4\ \text{pounds}/\text{feet}^3$

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2 years ago