Answer:
So you can cancel out the 16. See, the -16 is negative, and if we add +16 to it, then it cancels out and is 0. That way, you have x=1.
Step-by-step explanation:
-16x+x=-15
+16x +16
0+x=1
x=1
1. x=-5
2. x=10
3. x=4
4. x=5
5. x=8
6.x=10
FVAD=515[((1+0.18/12)^(12*2)-1)/(0.18/12)]*(1+0.18/12)
FVAD=14967.46
...........................
We need to correctly choose exactly 4 out of the 6 drawn numbers.
Apply hypergeometric distribution:
a=number of correctly chosen numbers = 4
A=number of correct (drawn) numbers = 6
b=number of incorrectly chosen numbers = 2
B=number of undrawn numbers = 44-6 = 38
Then by the hypergeometric distribution
P(a,b,A,B)
=C(A,a)C(B,b)/C(A+B,a+b) [C(n,r)=combination of r objects taken out of n]
=C(6,4)C(38,2)/C(44,6)
=15*703/7059052
= 10545/7059052
= 0.001494 (to the nearest millionth)
Answer: probability of winning third prize is 10545/7059052=0.001494
