Answer:
Explanation:
The 4 wires are connected in series: this means that the same current flow through them, and the voltage of the battery, V0, is equal to the sum of the voltages on each individual resistor:
Also, the equivalent resistance of the series circuit is
The voltage V2 across wire 2 is given by Ohm's law:
(1)
where I is the total current in the circuit, which is given by:
Substituting this into eq. (1), we find an expression for V2:
Explanation:
a) Given in the y direction (taking down to be positive):
Δy = 50 m
v₀ = 0 m/s
a = 10 m/s²
Find: t
Δy = v₀ t + ½ at²
50 m = (0 m/s) t + ½ (10 m/s²) t²
t = 3.2 s
b) Given in the x direction:
v₀ = 12 m/s
a = 0 m/s²
t = 3.2 s
Find: Δx
Δx = v₀ t + ½ at²
Δx = (12 m/s) (3.2 s) + ½ (0 m/s²) (3.2 s)²
Δx = 38 m
The resistance is increased when more and more bulbs are added to the circuit.
The answer to your question is true.