Answer:
P₂ = 1312.88 atm
Explanation:
Given data:
Initial temperature = 25°C
Initial pressure = 1250 atm
Final temperature = 40°C
Final pressure = ?
Solution:
Initial temperature = 25°C (25+273.15 = 298.15 K)
Final temperature = 40°C ( 40+273.15 = 313.15 k)
The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.
Mathematical relationship:
P₁/T₁ = P₂/T₂
Now we will put the values in formula:
1250 atm / 298.15 K = P₂/313.15 K
P₂ = 1250 atm × 313.15 K / 298.15 K
P₂ = 391437.5 atm. K /298.15 K
P₂ = 1312.88 atm
Answer:
you are not posted question
Answer:
785
Explanation:
Molecular. X. W
Weight
8000-16000 0.05 0.03
16000-24000. 0.017. 0.08
24000-32000. 0.22. 0.18
32000-40000. 0.25. 0.35
40000-48000. 0.22. 0.27
48000-56000. 0.09. 0.09
Mean weight X*M. W*M
12000. 600. 240
20000. 3200. 2000
28000. 6720. 5600
36000. 10080. 10800
44000. 8800. 11880
52000. 3640 3640
Total=33040g\mol 36240
Note before repeat molecular weight m= 3*12.01+6*1.008=
42.08g/mol
Degree of polymerization= total W*M/w=33040/42.08 =785