Answer:
1. 3.70 g Na₂CO₃·10H₂O
2. 50.0 mL of the first solution
Explanation:
1. Prepare the solution
(a) Calculate the molar mass of Na₂CO₃·10H₂O
The molar mass of Na₂CO₃·10H₂O is 286.15 g/mol.
(b) Calculate the moles of Na₂CO₃·10H₂O
(c) Calculate the mass of Na₂CO₃·10H₂O
2. Dilute the solution
We can use the dilution formula to calculate the volume needed.
V₁c₁ = V₂c₂
Data:
V₁ = ?; c₁ = 0.0500 mol·L⁻¹
V₂ = 100 mL; c₂ = 0.0250 mol·L⁻¹
Calculation:
Answer:
Atoms with 5 or more valence electrons gain electrons forming a negative ion, or anion. why are outermost electrons only ones included in orbital filling diagram? they are the only ones involved in chemical reactions and bonding. ... 2s orbital is farther from the nucleus meaning it has more energy.
Explanation:
Answer:
Explanation:
mass of the reactant = mass of the product
15.31 + 1.50 = 16.81g
Answer:
270.34
Explanation:
pressure, 550 pressure, 270.34
______________ = ___________
177 degree celsius. 87 degree celsius.
550 x 87 / 177 = 270.34