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2 years ago

How to obtain drinking water from muddy water

Chemistry

2 answers:

arsen [322]2 years ago

7 0

Answer:

by filtering it with filter paper

Stells [14]2 years ago

7 0

Filtering the water with a filter

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Red mercury (II) oxide decomposes to form mercury metal and oxygen gas according to the following equation: 2HgO (s) 2Hg (l) + O

diamong [38]

hey there!:

2HgO (s) => 2Hg (l) + O2 (g)

2 moles of HgO decompose to form 2 moles of Hg and 1 mole of O2 according to the reaction mentioned in the question.

So 4.00 moles of HgO must give 4 moles of Hg and 2 moles of O2 theoretically.

603 g of Hg = 603 / 200.6 = 3 moles

Percent yield = ( actual yield / theoretical yield) * 100

= ( 3/4) * 100

= 75 %

Hope this helps!

7 0

2 years ago

Read 2 more answers

Whether or not the process is observed in nature, which of the following could account for the transformation of gallium-67 to z

Sonja [21]

Answer:

Option a: positron emission.

Explanation:

In the transformation we have:

⁶⁷Ga → ⁶⁷Zn

The reaction is:

$^{67}_{Z}X \rightarrow ^{67}_{Z -1}Y$

For Ga to become Zn, the atom nucleus has to lose a proton, so in the given options, the reaction that involves the transformation of a proton is the option a, positron emission.

In a positron emission, a proton becomes into a neutron and a positron:

$^{A}_{Z}X \rightarrow ^{A}_{Z-1}Y + ^{0}_{+1}e$

Therefore, the correct answer is option a: positron emission.

I hope it helps you!

7 0

2 years ago

The net ionic equation for the reaction between aqueous sulfuric acid and aqueous sodium hydroxide is ________.

Kaylis [27]

Molecular equation:
$H_{2}SO_{4}(aq) + 2NaOH(aq)--\ \textgreater \ Na_{2}SO_{4}(aq) + 2H_{2}O(l)

Complete ionic equation:

2H^{+}+SO_{4}^{2-} + 2Na^{+} +2OH^{-}--\ \textgreater \ 2Na^{+}+SO_{4}^{2-} + 2H_{2}O(l)


Near 2H^{+},SO_{4}^{2-} , 2Na^{+} , OH^{-} 

should be written (aq).

Remove ions that do not change from both sides

2H^{+} + 2OH^{-}=2H_{2}O

Net ionic equation:

H^{+}(aq) + OH^{-}(aq)=H_{2}O(l)

Answer is D.

$

8 0

3 years ago

PLEASE HELP ME ASAP!!!

garik1379 [7]

I think unbalanced? not sure sorry

3 0

2 years ago

Read 2 more answers

Determine the concentration of a solution made by dissolving 44.0 g of calcium chloride (CaCl2) in 0.30 L of solution. SHOW YOUR

ycow [4]

Answer:

[CaCl₂] = 1.32 M

Explanation:

We know the volume of solution → 0.30 L

We know the mass of solute → 44 g of CaCl₂

Let's convert the mass of solute to moles.

44 g . 1 mol / 110.98 g = 0.396 moles

Molarity (mol/L) → 0.396 mol / 0.3 L = 1.32 M

6 0

2 years ago