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1 year ago

Which of the following best represents potential energy being converted to kinetic energy? HELP

Chemistry

1 answer:

TiliK225 [7]1 year ago

7 0

Answer:

B) A drawn bow is released, causing an arrow to fly across the field

Explanation:

Potential energy can be thought of as "potential" to do something. For eg, putting a ball on top of hill causes the ball to have the potential to roll down the hill if released. Here the ball converts the potential energy into kinetic energy (energy of motion) to roll down.

Similarly, the bow has been stretched (potential to fly if released), and when its released, it converts the potential energy into kinetic energy.

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What is the chemical formula of (Sodium hydroxide ) ??

Margaret [11]

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what is the chemical formula of (Sodium hydroxide ) ??

Sodium hydroxide, Sodium oxidanide

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2 years ago

This is how fluorine appears in the periodic table.9 F Flourine 19.00 What information does “9” give about an atom of fluorine?

siniylev [52]

The atomic number, the number of protons and the number of electrons.

8 0

2 years ago

Read 2 more answers

Calculate the standard free-energy change at 25 ∘C for the following reaction:

lianna [129]

Answer:

Standard free-energy change at $25^{0}\textrm{C}$ is $-3.80\times 10^{2}kJ/mol$

Explanation:

Oxidation: $Mg(s)-2e^{-}\rightarrow Mg^{2+}(aq.)$

Reduction: $Fe^{2+}(aq.)+2e^{-}\rightarrow Fe(s)$

--------------------------------------------------------------------------------------

Overall: $Mg(s)+Fe^{2+}(aq.)\rightarrow Mg^{2+}(aq.)+Fe(s)$

Standard cell potential, $E_{cell}^{0}=E_{Fe^{2+}\mid Fe}^{0}-E_{Mg^{2+}\mid Mg}^{0}$

So, $E_{cell}^{0}=(-0.41V)-(-2.38V)=1.97V$

We know, standard free energy change at $25^{0}\textrm{C}$ ( $\Delta G^{0}$ ): $\Delta G^{0}=-nFE_{cell}^{0}$

where, n is number of electron exchanged during cell reaction, 1F equal to 96500 C/mol

Here n = 2

So, $\Delta G^{0}=-(2)\times (96500C/mol)\times (1.97V)=-380210J/mol=-380.21kJ/mol=-3.80\times 10^{2}kJ/mol$

8 0

2 years ago

Read 2 more answers

A 1.25g sample of copper (cCu=0.386Jg∘C) is initially at a temperature of 25.0∘C. If the sample absorbs 87.4J of heat, what is i

professor190 [17]

Answer: Final temperature = 206∘C

Explanation:

Heat Energy is given as

q= mCΔT

ehere

q= Heat energy = 87.4J

m= mass=1.25g

C=specific heat c= 0.386Jg∘C) ,

ΔT = Change in temperate of which the final temperature= 25.0∘C

q= mCΔT

ΔT = q/mC

ΔT = 87.4/ 1.25 X 0.386=181.14∘C

But,

T final- T initial = ΔT

T final = T initial + ΔT

T final = 25.0∘C +181.14∘C=206.14∘C rounded to 206∘C

4 0

2 years ago

calculate the concentration in parts per million (ppm) of DDT if a sample size of 2000 g contained 0.050 g DDT

Firlakuza [10]

Answer:

= 25 ppm

Explanation:

PPM also refers to parts per million, it represents a low concentration of a solution. It represents 0.001 gram or a milligram in a 1000 mL, which equivalent to 1 mg per liter.

Given; a sample size of 2000 g contained 0.050 g DDT

It means, 2000 mL sample contained 50 mg DDT

Therefore in ppm we get;

= 50 mg/ 2 L

= 25 mg/L

<u>= 25 ppm</u>

4 0

2 years ago