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3 years ago

Which part of an atom is involved in chemical reactions?

Chemistry

2 answers:

algol [13]3 years ago

8 0

Answer:

a nucleus and its particles

Explanation:

torisob [31]3 years ago

5 0

Answer: Valence electrons are involved in a chemical reaction.

Explanation:

A chemical reaction takes place when there is an involvement of valence electrons. Bond formation involves either sharing of valence electrons or transfer of valence electrons. Bond breaking involves the separation of valence electrons.

When valence electrons are shared between the atoms, it leads to the formation of covalent bond.

When transfer of electrons takes place from one atom to another atom, it leads to the formation of ionic bond.

Hence, valence electrons are involved in a chemical reaction.

I think is A

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What is the molarity of a solution in which 25.3 grams of potassium bromide is dissolved in 150. mL of solution?

irga5000 [103]

Answer:

~1.417M

Explanation:

Molarity=(number of moles of solute)/(litres of solution)

In this case, we need to find moles of potassium bromide.

Mass=25.3g

Molar mass= 119g/mol

moles=(mass/molar mass)

=(25.3)/(119)

=0.2126moles of potassium bromide

Molarity=(0.2126)/(150/1000)

~1.417M

Hope this helps:)

6 0

2 years ago

Read 2 more answers

If a hydrogen atom and a helium atom have the same kinetic energy:________

Nuetrik [128]

Answer: If a hydrogen atom and a helium atom have the same kinetic energy then the wavelength of the hydrogen atom will be roughly equal to the wavelength of the helium atom.

Explanation:

The relation between energy and wavelength is as follows.

$E = \frac{hc}{\lambda}\\$

This means that energy is inversely proportional to wavelength.

As it is given that energy of a hydrogen atom and a helium atom is same.

Let us assume that $E_{hydrogen} = E_{helium} = E'$ . Hence, relation between their wavelengths will be calculated as follows.

$E_{hydrogen} = \frac{hc}{\lambda_{hydrogen}}$ ... (1)

$E_{helium} = \frac{hc}{\lambda_{helium}}$ ... (2)

Equating the equations (1) and (2) as follows.

$E_{hydrogen} = E_{helium} = E'\\\frac{hc}{\lambda_{hydrogen}} = \frac{hc}{\lambda_{helium}} = E'\\\lambda_{helium} = \lambda_{hydrogen} = E'$

Thus, we can conclude that if a hydrogen atom and a helium atom have the same kinetic energy then the wavelength of the hydrogen atom will be roughly equal to the wavelength of the helium atom.

7 0

2 years ago

8. 00 g of ethane gas, c2h6, is burned in oxygen. What volume of carbon dioxide gas is produced at 1. 00 atm and 25. 0°c?.

Sonbull [250]

Answer:

Explanation:1 g CH