Answer:
The correct answer is 187.7 J/Jg.
Explanation:
The formula for finding the specific heat of fusion is,
Specific heat of fusion = Q/m
Here Q is the heat energy added, signified in kJ, and m is the mass of the object in kg.
Based on the given information, the heat energy added or Q is 869 kJ and the mass of the ice is 4.6 Kg
Now putting the values in the formula we get,
Specific heat of fusion = Q/m
Specific heat of fusion = 863 kJ / 4.6 Kg = 187.7 J/Kg
Cart b because it has greater force and higher mass