Rotation about a carbon-carbon double bond does not readily occur because: __________.1) the overlap of the p orbitals of the ca
rbon-carbon π bond would be lost2) the double bond is much shorter and therefore more difficult to rotate3) the overlap of the sp2 orbitals of the carbon-carbon σ bond would be lost4) the double bond is much stronger and therefore more difficult to rotate
1 answer:
Answer:
1) The overlap of the p orbitals of the carbon-carbon π bond would be lost
Explanation:
Unlike simple bonds, a double bond can not rotate, since it is not possible to twist the ends of the molecule without breaking the π bond.
In the structure of but-2-ene present in the attachment, we can see the two isomers, <em>cis</em> and<em> trans</em>. These isomers cannot be interconverted by rotation around the carbon-carbon double bond without breaking the π bond.
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Answer:
(a) a = 5.08x10⁻⁸ cm
(b) r = 179.6 pm
Explanation:
(a) The lattice parameter "a" can be calculated using the following equation:
<em>where ρ: is the density of Th = 11.72 g/cm³, N° atoms/cell = 4, m: is the atomic weight of Th = 232 g/mol, Vc: is the unit cell volume = a³, and </em><em>: is the Avogadro constant = 6.023x10²³ atoms/mol. </em>
Hence the lattice parameter is:
(b) We know that the lattice parameter of a FCC structure is:
<em>where r: is the atomic radius of Th</em>
Hence, the atomic radius of Th is:
I hope it helps you!