Answer:
Q = 693 J
Explanation:
NaCl (aq) + AgNO₃ (aq) → AgCl (s) + NaNO₃ (aq)
Q = mcΔT
Q: heat
m: mass
c: specific heat
ΔT: temperature variation
Q = (50.0g + 100.0g) x (4.20 J/g°C) x (25.2°C - 24.1°C)
Q = 693 J
<u>Given:</u>
Volume of the unknown monoprotic acid (HA) = 25 ml
<u>To determine: </u>
The concentration of the acid HA
<u>Explanation:</u>
The titration reaction can be represented as-
HA + NaOH → Na⁺A⁻ + H₂O
As per stoichiometry: 1 mole of HA reacts with 1 mole of NaOH
At equivalence point-
moles of HA = moles of NaOH
For a known concentration and volume of added NaOH we have:
moles of NaOH = M(NaOH) * V(NaOH)
Thus, the concentration of the unknown 25 ml (0.025 L) of HA would be-
Molarity of HA = moles of HA/Vol of HA
Molarity of HA = M(NaOH)*V(NaOH)/0.025 L
Answer:
2 chlorine atoms.
Explanation:
H₂ + Cl₂ → 2HCl
The Law of Conservation of Mass states that matter can neither be created nor destroyed in a chemical reaction.
If 2 molecules of Hydrogen and 2 molecules of Chlorine is present in the reactants, the same no. of atoms should also be present in the product.
∴ the no. of chlorine atoms in the product is 2.
The answer is C. Here is the work:
<span>Moles=molarity * volume
2.5 * 0.5 = 1.25mols of NaCI
Mm of NaCI= 58.442468/mol
Multiply the moles by the Mm and you get the grams
1.25 * 58.442468 =73.1g
</span>
Answer:
1 that is 100%
Explanation:
here it is given that Fermi energy of the of the metal = 5 e.V
work function= 4 e.V
we have to find the probability that an incident electron will tunnel out if E=109 V/m
WORK FUNCTION : work function is defined as the energy required to withdraw an electron completely from the metal surface.
now the energy per unit volume in electric field is given by
E= 
E=
E=
in electron volt E=4.427\times 10^{6}joule × 6.24\times 10^{18}
E=
hence the applied energy per unit volume is greater than the work work function of electron so there is probability of 100% that electron will tunnel out
