Calculate the mass of NaCl required to prepare 0.5 liters of a 2.5 molar solution of NaCl.

1 answer:

8 0

The answer is C. Here is the work:

<span>Moles=molarity * volume
2.5 * 0.5 = 1.25mols of NaCI
Mm of NaCI= 58.442468/mol
Multiply the moles by the Mm and you get the grams
1.25 * 58.442468 =73.1g

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