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2 years ago

Complete the patterns

Mathematics

1 answer:

Rzqust [24]2 years ago

7 0

A. 0.02 0.2 2 20 200 2000
b. 3,400,000 , 34,000 , 340 ,3.4, 0.034
c. 85700 8,570 857 85.7 8.57 0.857
d. 444 4440 44,400 444,000 4,440,000 44,400,000
e. 0.095 9.5 950 95,000 9,500,000 950,000,000

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$\\ \sf\longmapsto x+5+x-5=80$

$\\ \sf\longmapsto 2x=80$

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2 years ago

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A company uses three different assembly lines- A1, A2, and A3- to manufacture a particular component. Of thosemanufactured by li

hammer [34]

Answer:

The probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.

Step-by-step explanation:

The three different assembly lines are: A₁, A₂ and A₃.

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It is given that:

$P (R|A_{1})=0.05\\P (R|A_{2})=0.08\\P (R|A_{3})=0.10\\P (A_{1})=0.50\\P (A_{2})=0.30\\P (A_{3})=0.20$

Compute the probability that a randomly selected component needs rework as follows:

$P(R)=P(R|A_{1})P(A_{1})+P(R|A_{2})P(A_{2})+P(R|A_{3})P(A_{3})\\=(0.05\times0.50)+(0.08\times0.30)+(0.10\times0.20)\\=0.069$

Compute the probability that a randomly selected component needs rework when it came from line A₁ as follows:

$P (A_{1}|R)=\frac{P(R|A_{1})P(A_{1})}{P(R)}=\frac{0.05\times0.50}{0.069} =0.3623$

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2 years ago

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SSSSS [86.1K]

Answer: -4

I can't show a number line because I'm on tablet.

Take away 4 from -8 and get -4

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2 years ago

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