Answer:The experimental probability and theoretical probability are equal.
Step-by-step explanation:
They will still have the same outcomes if is an experimental or theoretical probability.
This is a polygon with vertices on the lattice. Let's use Pick's Theorem,
A = (1/2) B + I - 1
where A is the area, B is the number of lattice points on the boundary and I is the number of lattice points in the interior.
In addition to the 3 vertices there are 3 more boundary points on UV and 6 more on WV, none on UV, B=3+3+6=12. In the interior I count I=9 lattice points.
A = (1/2) 12 + 9 - 1 = 14
Answer: 14
Obviously they just want us to say this is a right triangle, so the legs are altitude and base,
A = (1/2) b h (1/2) |UW| |WV| = (1/2) (4) (7) = 14
That checks.
5-1/10
Step-by-step explanation:
4-1/2+3/5=
9/2 + 3/5=
45/10+6/10=51/10=5-1/10
Answer:
96
Step-by-step explanation:
IT IS CONVENTIONAL to let the letter s symbolize the length of an arc, which is called arc length. We say in geometry that an arc "subtends" an angle θ; literally, "stretches under."
Now the circumference of a circle is an arc length. And the ratio of the circumference to the diameter is the basis of radian measure. That ratio is the definition of π.
π = C
D .
Since D = 2r, then
π = C
2r
or,
C
r = 2π .
arc lengthThat ratio -- 2π -- of the circumference of a circle to the radius, is called the radian measure of 1 revolution, which are four right angles at the center. The circumference subtends those four right angles.
arc length
Radian measure of θ = s
r
Thus the radian measure is based on ratios -- numbers -- that are actually found in the circle. The radian measure is a real number that indicates the ratio of a curved line to a straight, of an arc to the radius. For, the ratio of s to r does determine a unique central angle θ.
Answer:
(8) 
and 
(9) 
and 
(10) 
and 
Step-by-step explanation:
Given [Missing from the question]
Required
Write a system of linear equations
The solutions to this question is open and have different solutions
Solving (8) (-6,-2)
Let the equations be: x + y and 2x - y
--- (1)
-- (2)
So, the equations are:
and
Solving (9) (-12, 18)
Let the equations be: 3x - y and 4x + y
So, the equations are:
and
Solving (9): (2,0)
Let the equations be: x + y and x - y
So, the equations are:
and
