Answer? BRAINLIEST IF CORRECT

Mathematics

2 answers:

MrRa [10]2 years ago

8 0

Answer:

x = 4 and y =5

Step-by-step explanation:

6x-3y=9

-6x+6y=6

3y=15

y=5

6x-15=9 or -6x+30=6

6x=24 -6x=-24

x=4 x=4

BARSIC [14]2 years ago

8 0

Answer:

x is 4, y is 5

Step-by-step explanation:

Go answer it now fast fast

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Find an equation of the circle that satisfies the given conditions.

hodyreva [135]

The equation of a circle:
$(x-h)^2+(y-k)^2=r^2$
(h,k) - the coordinates of the centre
r - the radius

The midpoint of the diameter is the centre of a circle.
The coordinates of the midpoint:
$(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$
(x₁,y₁), (x₂,y₂) - the coordinates of endpoints

$P(-1,1) \\
x_1=-1 \\ y_1=1 \\ \\ Q(5,9) \\ x_2=5 \\ y_2=9 \\ \\
\frac{x_1+x_2}{2}=\frac{-1+5}{2}=\frac{4}{2}=2 \\ \frac{y_1+y_2}{2}=\frac{1+9}{2}=\frac{10}{2}=5$

The centre of the circle is (2,5).

The radius is the distance between an endpoint of the diameter and the centre.
The formula for distance:
$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$(-1,1) \\ x_1=-1 \\ y_1=1 \\ \\ (2,5) \\ x_2=2 \\ y_2=5 \\ \\ d=\sqrt{(2-(-1))^2+(5-1)^2}=\sqrt{3^2+4^2}=\sqrt{9+16}=\sqrt{25}=5$

The radius is 5.

$(x-2)^2+(y-5)^2=5^2 \\
\boxed{(x-2)^2+(y-5)^2=25}$

4 0

2 years ago

The function f is defined by f(x) = (x + 3)(x + 1).

blsea [12.9K]

Answer:

Below in bold.

Step-by-step explanation:

The zeroes ( = x-intercepts) are x = -3 and x = -1.

So the x -coordinate of the vertex is between x = -3 and x = -1.

The actual x-coordinate is halfway between these value: at x = -2.

7 0

2 years ago