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2 years ago

What are the three consecutive even integers that add up to 156

1 answer:

5 0

First, divide 156 by 3 (the amount of consecutive integers).
156 / 3 = 52
The middle consecutive integer is 52. Add and subtract 52 by 2.
52 - 2 = 50
52 + 2 = 54
Your three integers are 50, 52, and 54. Have an awesome day! :)

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The answer is (d) ⇒ $pq^{2}r\sqrt[3]{pr^{2}}$

Step-by-step explanation:

* To simplify the cube roots:

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then we divide the power by 3 to cancel the radical

If its variable we divide its power by 3 to cancel the radical

∵ $\sqrt[3]{p^{4}q^{6}r^{5}}=p^{\frac{4}{3}}q^{\frac{6}{3}}r^{\frac{5}{3}}}$

∴ $p^{\frac{4}{3}}q^{2}}r^{\frac{5}{3}}=p^{1\frac{1}{3}}q^{2}r^{1\frac{2}{3}}$

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