Answer: The correct option is (A) (2, -2).
Step-by-step explanation: Given that rectangle with vertices at K, L, M and N is graphed on the coordinate plane as shown in the figure.The figure is rotated 360° counterclockwise using the origin as the center of rotation.
We are to find the location of the image of point K after the rotation.
We know that
a rotation of 360° in counterclockwise direction about the origin map a point to itself. That is, the co-ordinates of the image point will be same as the original one.
From the figure, we see that the co-ordinates of point K are (2, -2).
Therefore, after rotation of 360° counterclockwise using the origin as the center of rotation,
the co-ordinates of the image of point K will also be (2, -2).
Thus, the location of the image of point K is (2, -2).
Option (A) is CORRECT.
If this is a parabolic motion equation, then it is a negative parabola, which looks like a hill (instead of a positive parabola that opens like a cup). Your equation would be h(t)= -16t^2 + 20t +3. That's the equation for an initial velocity of 20 ft/s thrown from an initial height of 3 ft. And the -16t^2 is the antiderivative of the gravitational pull. Anyway, if you're looking for the maximum height and you don't know calculus, then you have to complete the square to get this into vertex form. The vertex will be the highest point on the graph, which is consequently also the max height of the ball. When you do this, you get a vertex of (5/8, 9.25). The 9.25 is the max height of the ball.
Answer:
cos (A+B+C)
Step-by-step explanation:
as A,B,C, are triangle we have A,B and C as 180
cost
Answer:
I think b, but I may be wrong