Answer:
The strength of the electric field is 2.258 x 10⁸ N/C
Explanation:
Potential energy = -p*ECosθ
where;
d is the dipole moment
E is the electric field
θ is the angle of inclination
→When the water molecules is perpendicular to the field, θ =90° and potential energy = p*ECosθ = d*ECos0 = 0
Total potential energy = 0 + 1.40×10⁻²¹J, since it is 1.40×10⁻²¹J more
→When the water molecules is aligned to the field, θ =0°
potential energy = -p*ECosθ
dipole moment, p = 6.2×10⁻³⁰Cm
= -(6.2×10⁻³⁰)*(E) Cos0
0 + 1.40×10⁻²¹ J = -(6.2×10⁻³⁰)*(E),
E = (1.40×10⁻²¹ J)/(6.2×10⁻³⁰)
E = 2.258 x 10⁸ N/C
Therefore, the strength of the electric field is 2.258 x 10⁸ N/C