The component of the weight of the box along the surface is 34.9N.
<u>Explanation:</u>
Given that
Mass of the box m=21kg
Angle of inclination θ=10°
Acceleration due to gravity g=9.8
Weight of an object is the force with which the earth attracts the object. Since weight is a force its unit is Newton(N). When an object is placed on a surface that has no inclination, its weight is given by the expression
W=mg
where m denotes mass of the object and g denotes the acceleration due to gravity.
When the surface has an inclination, the weight of the object can be resolved into two components that are parallel and perpendicular to the surface.
The component of weight parallel to the surface is given by
W=mgsinθ
where θ is the angle of inclination
The component of weight perpendicular to the surface is given by
W=mgcosθ
In the given problem, we have to find out the parallel component of weight
W=mgsinθ
The component of the weight of the box along the surface is 34.9N
Answer:
The tangential acceleration of the pedal is 0.0301 m/s².
Explanation:
Given that,
Length = 19 cm
Diameter = 23 cm
Time = 10 sec
Initial angular velocity = 65 rpm
Final velocity = 90 rpm
Suppose we need to find the tangential acceleration of the pedal
We need to calculate the tangential acceleration of the pedal
Using formula of tangential acceleration
Hence, The tangential acceleration of the pedal is 0.0301 m/s².
Answer:
Explanation:
We know that from Newton's second law of motion, F=ma hence making acceleration the subject then where a is acceleration, F is force and m is mass
Also making mass the subject of the formula
For and hence
Not sure what you mean but I think you are either talking about a lunch box or a thermos