Slope-intercept form is y = mx + b
So we can manage to do this:
(y - yo) = m.(x - xo)
Where (x, y) and (xo, yo) are points of this line, this way we can discover the slope.
(7 - 2) = m.(1 - 0)
5 = m
m = 5
So,
y = 5x + b
Now we still have to use (y - yo) = m.(x - xo), but this time we will put only 1 point and the slope.
(y - yo) = m.(x - xo)
(y - 2) = 5.(x - 0)
y - 2 = 5x
y = 5x + 2
So, this is the line in slope-intercept form.
A field is a unit of data consisting of one or more characters(bytes).
Graphically I guess means graph it.
First graph goes to first problem. Second graph goes to second problem.
ANSWER
No solution
EXPLANATION
The first equation is
and the second equation is
We equate the two equations to obtain;
This implies that
There is no real number whose square is -1.
Therefore, the equation has no solution.
Answer:
They have the same x-value
f(x) has the greater minimum
Step-by-step explanation:
To find the vertex of a second degree equation, in this case the minimum value, we can use the following equation:
x = -b / 2a
Remember that a second degree equation has the following form:
ax^2 + bx + c
so a = 1, b = -8 and c = 7. Now you have to substitute in the previous equation
x = - (-8) / 2(1)
x = 8 / 2
x = 4
This means that the two functions have the same x-value.
The y value of f(x) would be
f(4) = (4)^2 - 8(4) + 7
f(4) = 16 - 32 + 7
f(4) = -9
So the vertex, or minimun value of f(x) would be at the point (4, -9).
The vertex, or minimun value of g(x) is at the point (4, -4).
So f(x) has a minimum value of -9 and g(x) a minimum value of -4.
