We are given the equations 3x+5y=-3 and x-5y=-5.
Both equations have a 5y term which allows us to easily solve the system by elimination. To do so we will add the equations together like a simple addition problem by adding the x terms together, the y terms together, and the integer answers together.
3x + 5y = -3
+x - 5y = -5
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4x + 0y = -8
The y terms cancel out since one is positive and one is negative. Now we can solve for x.
4x = -8
x = -2
Now plug -2 in for x in one of the original equations to find y.
(-2) - 5y = -5
-5y = -3
y = 3/5
Our answer as an ordered pair is (2, 3/5)
Answer:
I assume you mean 16^(1/3) i.e. the cube root of 16
I am also assuming you mean the real cube root because, as you may know, every non-zero real number has three cube root - one real and two complex conjugates.
Since 16 = 8 x 2 and 8 = 2³ then (2³ x 2)^1/3 = (2³)^1/3 x 2^1/3 = 2 x 2^1/3
You might check that the cube root of 16 is about 2.52 which is twice the cube root of 2
Step-by-step explanation:
Answer:
a) (4,5)
b) (0,-3)
Step-by-step explanation:
We have to perform the following reflection over given ordered pair.
a) Reflect the ordered pair (-4,5) across the y-axis
Reflection over y-axis:
Thus, (-4,5) will be reflected over y-axis as
b) Reflect the ordered pair (0,3) across the y-axis
Reflection over x-axis:
Thus, (0,3) will be reflected over x-axis as
Answer:
1200000
Step-by-step explanation: