Answer: They have the same x-value f(x) has the greater minimum Step-by-step explanation: To find the vertex of a second degree equation, in this case the minimum value, we can use the following equation: x = -b / 2a Remember that a second degree equation has the following form: ax^2 + bx + c so a = 1, b = -8 and c = 7. Now you have to substitute in the previous equation x = - (-8) / 2(1) x = 8 / 2 x = 4 This means that the two functions have the same x-value. The y value of f(x) would be f(4) = (4)^2 - 8(4) + 7 f(4) = 16 - 32 + 7 f(4) = -9 So the vertex, or minimun value of f(x) would be at the point (4, -9). The vertex, or minimun value of g(x) is at the point (4, -4). So f(x) has a minimum value of -9 and g(x) a minimum value of -4.
