Answer:
Change in potential energy = 7350 Joules
Explanation:
It is given that,
Side of cube, a = 0.5 m
Density of cube,
The cube is lifted vertically by a crane to a height of 3 m
We know that, density
So, m = d × V (V = volume of cube = a³)
m = 250 kg
We have to find the change in potential energy of the cube. At ground level, the potential energy is equal to 0.
Potential energy at height h is given by :
PE = 250 kg × 9.8 m/s² ×3 m
PE = 7350 Joules
So, change in potential energy of the cube is 7350 Joules.
Answer:
The current would be same in both situation.
Explanation:
Given that,
Current I = 13 A
Number of turns = 23
We need to calculate the induced emf
Using formula of induced emf is
For N = 1
We need to calculate the current
Using formula of current
Put the value of emf
Now, if the number of turn is 22 , then induced emf would be
Then the current would be
Hence, The current would be same in both situation.
Answer:
True
Explanation:
East, up, and left all define as a direction.
Uhhhh...you should have paid attention in class, just saying...