To find the distance, you need to subtract the second point from the first one. So:
0 - (-9) = 9 ( two minuses turn into a positive)
And
7 - (-5) = 12
So the difference between the points is 9 units on the x- axis and 12 on the y-axis.
Hope this helped and pls mark as brainliest!
~Luna
All the measures in a triangle are equal to 180 degrees.
Let the unknown angle= x.
40+89+x= 180
Combine like terms.
129+x= 180
Subtract 129 from both sides.
x= 51
The angle is equal to 51.
I hope this helps!
~kaikers
Answer:A) What are the side lengths of the original triangle, ABC?
B) What are the side lengths of the enlarged, A’B’C?
C) Calculate the area and the perimeter of A’B’C.
Answer:
3.58
Step-by-step explanation:
Given :
y = 2x + 4 -------- eq1
y = 2x - 4 -------- eq2
sanity check : both equations have same slope, so we can conclude that they are both parallel to one another.
Step 1: consider equation 1, pick any random x-value and find they corresponding y-value. we pick x = -2
This gives us y = 2(-2) + 4 = 0
Hence we get a point (x,y) = (-2,0)
Step 2: express equation 2 in general form (i.e Ax + By + C = 0)
y = 2x-4 -------rearrange---> 2x - y -4 = 0
Comparing with the general form, we get A = 2, B = -1, C = -4
Recall that the distance between 2 parallel lines is given by the attached formula (see attached picture).
substituting the values for A, B, C and (x, y) from the previous step:
d = | (2)(-2) + (-1)(0) + (-4) | / √(2² + (-1)²)
d = | -4 + 0 - 4 | / √(4 + 1)
d = | -8 | / √5
d = 8 / √5
d = 3.5777
d = 3.58 (rounded 2 dec. pl)
All you do is multiply 60 * 40 = 2400 ft squared. you find area of a square by multiplying base * length. SO the answer is "D"