Answer:
A & F
Step-by-step explanation:
if you look at the other question I answered for you, you can see the work. but basically you can figure out slope by doing m=y2-y1/x2-x1.
so we now know the slope is 1/4. which eliminates choices B, D, E.
we see that C will not work because the x and y values are switched.
according to point slope formula A & F work.
What do you mean what’s the question
<span><span><span>2<span>(2^2)</span></span>(3)</span><span>(2^2)
</span></span><span><span><span>2<span>(2^2)</span></span>(3)</span><span>(2^2)
</span></span><span>=96</span>
This a pretty typical right triangle trig problem; the first step is to figure out what we have and what we want in relation to an acute angle in the problem.
Here we have a right triangle, G=90°, and we're given angle F=23°. So we have to name everything in relation to F.
31 = FG is <em>adjacent </em>to F.
x = GE is <em>opposite </em>to F.
OK, we have an opposite and adjacent; that tells us we need to use the tangent of F. Let's write it:
tan 23° = tan F = opp/adj = x/31
Solving,
x = 31 tan 23°
I hate the calculator part. I used to love that part.
x = 31 tan 23° ≈ 13.16 feet
Answer: 4) x ≈ 13.2 ft
Answer:
B=23.19
Step-by-step explanation:
First, find the last side of the triangle using the Pythagorean theorem.
![a^{2} +b^{2} =c^{2} \\21^{2} +9^{2} =c^{2} \\441+81=c^{2} \\\sqrt[3]{58}=c](https://tex.z-dn.net/?f=a%5E%7B2%7D%20%2Bb%5E%7B2%7D%20%3Dc%5E%7B2%7D%20%5C%5C21%5E%7B2%7D%20%2B9%5E%7B2%7D%20%3Dc%5E%7B2%7D%20%5C%5C441%2B81%3Dc%5E%7B2%7D%20%5C%5C%5Csqrt%5B3%5D%7B58%7D%3Dc)
Then, find the missing angle, lets name it B.
The angle B can be found using the inverse sine function.
B=arcsin(opp/hyp)
![B=arcsin(\frac{9}{\sqrt[3]{58} } )\\B=23.19](https://tex.z-dn.net/?f=B%3Darcsin%28%5Cfrac%7B9%7D%7B%5Csqrt%5B3%5D%7B58%7D%20%7D%20%29%5C%5CB%3D23.19)
