How many moles of hydrogen are in 3. 06 × 10⁻³ g of glycine , c₂h₅no₂?.
1 answer:
Answer:
n = 6.06 x mol
Explanation:
n =?
m = 3.06 x 10-³ g
M (H5) = 5 x 1.01 (Since we only want hydrogen)
Atomic mass of C = 12.01
Atomic mass of H is 1,01, etc.
Having this data, we can use the Molar mass formula and change it so we can know the quantity of matter (n) in moles, and we just replace it.
M = ⇔ n =
⇔ n =
⇔ n = 6.06 x
mol
Note: The numbers I've used may be different from yours, by a small difference. I don't know if it's the case, but hope it helped.
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Answer : The value of for this reaction is 36.18 kJ
Explanation :
First law of thermodynamic : It states that the energy can not be created or destroyed, it can only change or transfer from one state to another state.
As per first law of thermodynamic,
where,
= internal energy of the system
q = heat added or rejected by the system
w = work done
As we are given that:
q = 38.65 kJ
w = -2.47 kJ (system work done on surrounding)
Now put all the given values in the above expression, we get:
Therefore, the value of for this reaction is 36.18 kJ
The masses of the components are obtained as;
- Sodium hydrogen carbonate = 3.51 g
- Sodium carbonate = 8.708 g
The term decomposition has to do with the breakdown of the given substance into its components. The components of sodium hydrogen carbonate could be identified as water vapor, carbon dioxide gas and sodium carbonate. Among these products that have been listed here, we can see that it is only the sodium carbonate that remains as a solid. The others are gases that move away from the system that is under study.
Now putting down the equation of the reaction, we have;
Now, the loss in mass must be due to the carbon dioxide and the water. Hence we obtain the loss in mass to be 10.000 g - 8.708 g = 1.292 g
Mass of sodium hydrogen carbonate = 2 * 88 g/mol * 1.292 g/62 g/mol
= 3.51 g
Learn more about anhydrous sodium carbonate :brainly.com/question/20479996
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