<span>0.496 g of NaOH required
3 pellets.
First, determine the molar mass of NaOH.
Atomic weight sodium = 22.989769
Atomic weight hydrogen = 22.989769
Atomic weight oxygen = 15.999
Molar mass NaOH = 22.989769 + 22.989769 + 15.999 = 61.978538 g/mol
Now determine how many moles of NaOH we need. Multiply desired volume by desired molarity. So
0.200 l * 0.040 mol/l= 0.008 mol
To get the mass, then multiply by the molar mass, so
0.008 mol * 61.978538 g/mol = 0.495828304 g
Since we have the NaOH in pellet form, divide the desired mass by the mass of each pellet. So
0.495828304 g / 0.170 g/pellet = 2.916637082 pellets
You'll need 3 pellets.
To get closer to the desired molarity, I would recommend increasing the amount of solution being prepared if you can accurately measure the larger volume.</span>
Answer:
247.2g
Explanation:
Using the general gas law equation as follows:
PV = nRT
Where;
P = pressure (atm)
V = volume (L)
n = number of moles (mol)
R = gas law constant (0.0821 Latm/molK)
T = temperature (K)
According to the information in this question, a fuel tank contains 150. L (V) of H2 gas at 20.0 atm (P) at 25.0˚C (T)
Temperature = 25°C = 25 + 273 = 298K
Using PV = nRT
20 × 150 = n × 0.0821 × 298
3000 = 24.4658n
n = 3000/24.4658
n = 122.62
n = 122.6mol
Using the formula, mole = mass/molar mass, to find the mass of H2 gas.
Molar mass of H2 = 1.008(2)
= 2.016g/mol
122.6 = mass/2.016
mass = 122.6 × 2.016
mass = 247.2g.
Metal is a conductor of heat
it has 5 electrons in it's outermost shell.
s 2e- , p 5e-
