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1 year ago

Hint: Choose 3. Linear functions create straight lines and can be written as y= mx + b

Mathematics

1 answer:

babymother [125]1 year ago

3 0

Answer:

A, E and the chart on th botton (I cant see the letter)

Step-by-step explanation:

A. y+4 = 2x --> y=2x-4

The 2 is the M and the -4 is the b

E. E is a diagional line theirfore it is linnear.

Chart on the bottom. The chart wiht points: (-2, 2.5) (-1, 2.75) (0,3) (1, 3.25) and (2,3.5)

If you graph it then it will be a diagional line.

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0.3 ÷ 42 Will someone please help me with the method on how to do this it is very hard.

slamgirl [31]

The answer is 1/140

Work Shown

0.3 / 42

Convert and Rewrite

3/10 x 1/42

Reduce The Numbers With the greatest Common divisor 3

1/10 x 1/14

Multiply the fractions

1/140 or

AlTernative Form 0.007114285 , -1 over 140

I Hope This Help

-Dante

3 0

2 years ago

What is the slope of the line that passes through the points (0, -4) and (30, – 9)?

Softa [21]

Answer:

-1/6

Step-by-step explanation:

the slope is -1/6

6 0

1 year ago

Please help me I really need it if I get this wrong I will fail the quiz.

galben [10]

Answer: C.) 6 feet describes the center, and 9 feet describes the spread.

Step-by-step explanation: Center is the median/mean, spread is the range. If I am reading this right, they basically gave the answer to you. The mean is 6 feet, and the range is 9 feet. I hope this helps you! If I got it wrong, please let me know so I can correct my errors.

4 0

3 years ago

Use a power series to approximate the value of the integral with an error of less than 0.0001. (Round your answer to four decima

otez555 [7]

Answer:

The answer is "0.9461"

Step-by-step explanation:

Given:

$\int^1_0 \frac{sin(x)}{x} dx\\\\$

$\int^1_0 \frac{sin(x)}{x} dx\\\\$ ≈ $\sum^2_{n=0}\frac{(-1)^n x^{2n+1} (-1)^n (x-1)^n}{(2n + 1)!}$

$\therefore$

$\to \sin x = \sum^{\infty}_{n=0} (-1)^n\frac{x^{(2n+1)}}{(2n + 1)!}$

$\because \\\\ \to \frac{\sin x}{x} =\sum^{\infty}_{n=0} (-1)^n \frac{x^{2n+1-1}}{(2n+1)!}\\$

$=\sum^{\infty}_{n=0} (-1)^n \frac{x^{2n}}{(2n+1)!}$

The value is in between 0 and 1 then:

$\to \int^1_0 \frac{sin(x)}{x} = =\sum^{2}_{n=0} \frac{(-1)^n}{ (2n+1) (2n+1)!}$

The above-given series is an alternative series, and it will give an error, when the nth term is bounded by its absolute value, that can be described as follows:

$\to \frac{1}{(2n+3) (2n+3)!}< 0.0001\\\\\to (2n+3) (2n+3)!> 0.0001\\\\\to n\geq 2 \\$

So,

$\int^1_0 \frac{sin(x)}{x} dx\\\\$ ≈ $1 - \frac{1}{3 \cdot 3!}+\frac{1}{5 \cdot 5!}\\\\$

$\approx 1 - \frac{1}{3 \cdot 6}+\frac{1}{5 \cdot 120}\\\\\approx 1 - \frac{1}{18}+\frac{1}{600}\\\\\approx 1 - \frac{1}{18}+\frac{1}{600}\\\\\approx \frac{18-1}{18}+\frac{1}{600}\\\\\approx \frac{17}{18}+\frac{1}{600}\\\\\approx \frac{1700+3}{1800}\\\\ \approx \frac{1703}{1800}\\\\\approx 0.9461$

5 0

2 years ago

Will crown the correct answers brainliest 3x

Solnce55 [7]

Answer :

(1) $\frac{1}{x}+\frac{1}{y}=\frac{y+x}{xy}$

(2) $\frac{1}{5x}+\frac{1}{3y}=\frac{3y+5x}{15xy}$

(3) $\frac{1}{7x}-\frac{1}{2y}=\frac{2y-7x}{14xy}$

(4) $\frac{2}{5x}+\frac{3}{7y}=\frac{6y+15x}{21xy}$

(5) $\frac{7}{11x}-\frac{1}{33y}=\frac{231y-11x}{363xy}$

(6) $\frac{1}{2x}+\frac{3}{x}-\frac{1}{7y}=\frac{7y+42y-2x}{14xy}$

Step-by-step explanation :

(1) The given expression is: $\frac{1}{x}+\frac{1}{y}$

$\frac{1}{x}+\frac{1}{y}=\frac{y+x}{xy}$

(2) The given expression is: $\frac{1}{5x}+\frac{1}{3y}$

$\frac{1}{5x}+\frac{1}{3y}=\frac{3y+5x}{(5x)\times (3y)}=\frac{3y+5x}{15xy}$

(3) The given expression is: $\frac{1}{7x}-\frac{1}{2y}$

$\frac{1}{7x}-\frac{1}{2y}=\frac{2y-7x}{(7x)\times (2y)}=\frac{2y-7x}{14xy}$

(4) The given expression is: $\frac{2}{5x}+\frac{3}{7y}$

$\frac{2}{5x}+\frac{3}{7y}=\frac{(2\times 3y)+(3\times 5x)}{(5x)\times (7y)}=\frac{6y+15x}{21xy}$

(5) The given expression is: $\frac{7}{11x}-\frac{1}{33y}$

$\frac{7}{11x}-\frac{1}{33y}=\frac{(7\times 33y)-(1\times 11x)}{(11x)\times (33y)}=\frac{231y-11x}{363xy}$

(6) The given expression is: $\frac{1}{2x}+\frac{3}{x}-\frac{1}{7y}$

$\frac{1}{2x}+\frac{3}{x}-\frac{1}{7y}=\frac{(x\times 7y)+(3\times 2x\times 7y)-(2x\times x)}{(2x)\times (x)\times (7y)}=\frac{7xy+42xy-2x^2}{14x^2y}=\frac{7y+42y-2x}{14xy}$

7 0

2 years ago