Hello!
To solve this, lets put it into a system of equations where w=width and L=length.
2w+2L=80
L-8=w
To solve, we see that w=L-8. We can substitute this in the first equation to find L and then w.
2(L-8)+2L=80
2L-16+2L=80
4L-16+80
4L-16=80
4L=96
L=24
Now that we know L=24, we can find w. 24-8=16. Now we know that L=24 and w=16.
Lets check our answer. In our original system of equations, we have 48+32=80, which is true, and 24-8=16. Also, the perimeter must equal 80. 16+16+24+24=80.
As our final answer, the width of the pool is 16 feet, and the length is 24 feet.
Hope this helps!
Answer:
a) 121,000
b)8.35 x 10^-6
Step-by-step explanation:
By HA (hypotenuse is the same and angles are equal)
Answer: b) Large blue t-shirt & Medium RC jeans
<u>Step-by-step explanation:</u>
The subscript numbers attached to the matrix letter represents the:
ROW, COLUMN
![A=\left[\begin{array}{ccc}a_{1,1}&a_{1, 2}&a_{1, 3}\\a_{2,1}&a_{2, 2}&a_{2, 3}\\a_{3,1}&a_{3, 2}&a_{3, 3}\end{array}\right] \qquad B=\left[\begin{array}{ccc}a_{1,1}&b_{1, 2}&b_{1, 3}\\b_{2,1}&b_{2, 2}&b_{2, 3}\\b_{3,1}&b_{3, 2}&b_{3, 3}\end{array}\right]\\](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da_%7B1%2C1%7D%26a_%7B1%2C%202%7D%26a_%7B1%2C%203%7D%5C%5Ca_%7B2%2C1%7D%26a_%7B2%2C%202%7D%26a_%7B2%2C%203%7D%5C%5Ca_%7B3%2C1%7D%26a_%7B3%2C%202%7D%26a_%7B3%2C%203%7D%5Cend%7Barray%7D%5Cright%5D%20%5Cqquad%20B%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da_%7B1%2C1%7D%26b_%7B1%2C%202%7D%26b_%7B1%2C%203%7D%5C%5Cb_%7B2%2C1%7D%26b_%7B2%2C%202%7D%26b_%7B2%2C%203%7D%5C%5Cb_%7B3%2C1%7D%26b_%7B3%2C%202%7D%26b_%7B3%2C%203%7D%5Cend%7Barray%7D%5Cright%5D%5C%5C)
A₁,₃ = 1st row, 3rd column
1st row is Blue, 3rd column is Large
B₃,₂ = 3rd row, 2nd column
3rd row is RC jeans, 2nd column is Medium
A₁,₃ + B₃,₂ = Large blue t-shirt & Medium RC jeans
