The first-serve percentage of a
tennis player in a match is normally distributed with a standard deviation of
4.3%. If a sample of 15 random matches of
the player is taken, the mean
first-serve percentage is found to be 26.4%. The margin of error of the sample
mean is 83.71%.
I’m pretty sure it’s c , sorry if it’s wrong tho
Answer:
6x² - x - 12
Step-by-step explanation:
Each term in the second factor is multiplied by each term in the first factor.
(2x - 3)(3x + 4)
= 2x(3x + 4) - 3 (3x + 4) ← distribute both parenthesis
= 6x² + 8x - 9x - 12 ← collect like terms
= 6x² - x - 12 ← in expanded form
I hope this helps you out
The answer to the equation is b