Please help me with this question

Mathematics

2 answers:

Anettt [7]2 years ago

5 0

Slope: 3
y: intercept 0
slope is negative(when the line goes down from left to right it’s negative, and the y-intercept is the number on the y axis while the slope is found by using rise over run method meaning y value over x value in fraction form

Andreyy892 years ago

4 0

Answer:

the slope is -3, the slope is negative, the y-intercept is 0

Step-by-step explanation:

this ones are the ones that apply to the graph

You might be interested in

Explain how you would find the sum of 46+7

Darya [45]

Answer: Method of finding the sum of 46 and 7 is mentioned in below explanation.

Step-by-step explanation:

According to the question, we have to find out 46+7

First, we need to add 6 and 7 by that we get the result 13.

Where, 3 will be the digit in once place of our answer.

And, we need to add 1 in 4, that is 5 by that we get the tenth place digit of our result. which is 5.

So, our complete answer is 53.

8 0

2 years ago

Read 2 more answers

Find e-0.3 A) -0.74 B) 0.74 C) -1.35

deff fn [24]

E^-0.3 = 0.74 from the calculator

4 0

2 years ago

Desperate Please Hurry Question down below

VladimirAG [237]

Answer:

See below

Step-by-step explanation:

I'm guessing you want to fill in the blanks of the sequence?

We can represent this as an equation:

31-3x=18

-3x=13

x=-13/3

Second term: 31 - (13/3) = 26 2/3

Third term: 26 2/3 - (13/3) = 22 1/3

4 0

1 year ago

Please explain thanks

Gre4nikov [31]

<h3>Answer:</h3>

$\large\boxed{\pink{\sf \leadsto Value \ of \ LM \ is \ 11 \ units . }}$

<h3>Step-by-step explanation:</h3>

A figure is given to us in which we can see two triangles one is ∆ MPL and other is ∆MPN .

Figure :- 

$\setlength{\unitlength}{1 cm}\begin{picture}(12,12)\linethickness{0.25mm}\put(0,0){\line(1,2){2}} \put(0.001,0){\line(1,0){4}}\put(2,0){\vector(0,1){5}}\put(4,0){\line( - 1,2){2}}\put(0,-0.4){$\bf L $}\put(2,-0.4){$\bf P$}\put(4,-0.4){$\bf N $}\put(2.2,4){$\bf M $}\put(2.8, - .4){$\bf 5 $}\put(1, - .4){$\bf 5 $}\put(3.4, 2){$\bf 11 $}\put(2.3,0){\line(0,1){.3}}\put(2.3,.3){\line( - 1,0){.3}}\end{picture}$