BRAINLIST!!!
1 answer:
You might be interested in
Answer:
103.5 meters
Explanation:
Given that a stunt person has to jump from a bridge and land on a boat in the water 22.5 m below. The boat is cruising at a constant velocity of 48.3 m/s towards the bridge. The stunt person will jump up at 6.45 m/s as they leave the bridge.
The time the person will jump to a certain spot under the bridge can be calculated by using the formula below:
h = Ut + 1/2gt^2
since the person will fall under gravity, g = 9.8 m/s^2
Also, let assume that the person jump from rest, then, U = 0
Substitute h, U and g into the formula above
22.5 = 1/2 * 9.8 * t^2
22.5 = 4.9t^2
22.5 = 4.9t^2
t^2 = 22.5/4.9
t^2 = 4.59
t =
t = 2.143 seconds
From definition of speed,
speed = distance /time
Given that the boat is cruising at a constant velocity of 48.3 m/s towards the bridge, substitute the speed and the time to get the distance.
48.3 = distance / 2.143
distance = 48.3 * 2.143
distance = 103.5 m
Therefore, the boat should be 103.5m away from the bridge at the moment the stunt person jumps?
Answer:
(a). The velocity of the object is -2.496 m/s.
(b). The total distance of the object travels during the fall is 23.80 m.
Explanation:
Given that,
Time = 1.95 s
Distance = 23.5 m
(a). We need to calculate the velocity
Using equation of motion
Put the value into the formula
(b). We need to calculate the total distance the object travels during the fall
Using equation of motion
Put the value in the equation
The total time is
We need to calculate the distance
Using equation of motion
Put the value into the formula
Hence, (a). The velocity of the object is -2.496 m/s.
(b). The total distance of the object travels during the fall is 23.80 m.