Answer:
About 3.88 meters per second
Explanation:
14km= 14,000m
14,000m per hour
so 14,000 ÷ 60= 233.33 meters per minute
233.33÷60=3.88 meters per second
Answer:
C. The motor tasks performed in the experiment were too simple.
On this case is the best option since the student wants to explain the effect of motor imagery and action observation together into the excitability. And maybe is too simple, since we need to cover other possibilities in order to analyze the excitability.
Explanation:
A. The procedure used did not include MEP recordings prior to each task.
Not true, is not a requisite record MEP prior to the task to evaluate the variable of interest on this case.
B. MEP amplitudes in an individual are typically highly consistent.
The Motor evoked potentials (MEP) "are electrical signals recorded from neural tissue or muscle after activation of central motor pathways". But on this case that's a technical aspect related to the topic and this not would be the reason why we need to withhold the presentation
C. The motor tasks performed in the experiment were too simple.
On this case is the best option since the student wants to explain the effect of motor imagery and action observation together into the excitability. And maybe is too simple, since we need to cover other possibilities in order to analyze the excitability.
D. The six different conditions were run in random order.
That's not true the student are not analyzing 6 different conditions, just 2.
Answer:
Mass of the silver will be equal to 46.70 gram
Explanation:
We have given heat required to raise the temperature of silver by 24°C is 269 J , so
Specific heat of silver = 0.240 J/gram°C
We have to find the mass of silver
We know that heat required is given by
, here m is mass, c is specific heat of silver and is rise in temperature
So
m = 46.70 gram
So mass of the silver will be equal to 46.70 gram
Answer:N=0
Explanation:
Given
both blocks experiencing free fall so net weight of block during free fall is zero thus there is no normal reaction between them.
N=0
Answer: If you use a very small resistance AND the circuit design is such that the voltage drop is across the resistance of the heating-wire-circuit, [nothing else in the circuit is limiting current flow] you will get more heating. That's what we have in a heat anticipator internal-nichrome-wire-heater device.
Explanation: