To solve this problem you must apply the proccedure shown below:
1- If the triangle is a rigth triangle, you must apply the Pythagorean Theorem. Taking the length 3 inches as the hypotenuse, which is the longest side of the triangle, you have:
a^2=b^2+c^2
c=√(a^2-b^2)
b=3/4 inches
a=3 inches
2- When you susbtitute the values, you obtain:
c=√(3 inches)^2-(3/4 inches)^2
c=2.90 inches
The answer is: 2.90 inches.
The question is an illustration of combination and there are 729 potential pass codes available
<h3>How to determine the number of potential pass codes?</h3>
The given parameters are
Symbols available = 9
Length of pass code = 3
From the question, we understand that a symbol may be entered any number of times.
This means that each of the 9 available symbols can be used three times
So, the number of potential pass codes is
Passcodes = 9 * 9 * 9
Evaluate the product
Passcodes = 729
Hence, there are 729 potential pass codes available
Read more about combination at:
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The highest pre-tax price I can pay =x
I suggest this equation:
x+(8/100)x=120
least common multiple=100
100x+8x=12000
108x=12000
x=12000/108
x=111.11111...≈111.11$
The highest pre-tax price that i can pay without going over budget is $111.11