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1 year ago

Newtons third law of motion the lab questions are in the paper

2 answers:

4 0

Newton's third law states that when two bodies interact, they apply forces to one another that are equal in magnitude and opposite in direction. The third law is also known as the law of action and reaction. ... For example, a book resting on a table applies a downward force equal to its weight on the table.

Rama09 [41]1 year ago

3 0

Answer:

Sir Isaac Newton was an English scientist. He was born in 1642 and died in 1727. This was around the time of the early colonization of North America: the founding of some of the original 13 colonies, the French and Indiana wars and the Salem witch trials, but before the American Revolution.

Newton is best known for three very important principles of physics called classical mechanics. These principles describe how things move and are referred to today by his name - Newton's Laws of Motion. There are three of them, Newtons First, Second and Third Law of Motion. Today's experiment will demonstrate Newton's Third Law of Motion: for every action there is an equal and opposite re-action. SIMPLY: If you push an object, that object pushes back in the opposite direction equally hard.

Explanation:

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2 years ago

5. An acrobat, starting from rest, swings freely on a trapeze of

34kurt

The energy conservation and trigonometry we can find the results for the questions about the movement of the acrobat are;

a) The maximum speed is v = 4.89 m / s

b) The maximum height is h = 1.22 m

The energy conservation is one of the most fundamental principles of physics, stable that if there are no friction forces the mechanistic energy remains constant. Mechanical energy is the sum of the kinetic energy plus the potential energies.

Em = K + U

Let's write the energy in two points.

Starting point. Highest part of the oscillation

Em₀ = U = m g h

Final point. Lower part of the movement

$Em_f$ = K = ½ m v²

Energy is conserved.

Emo = $Em_f$

m g h = ½ m v²

v² = 2 gh

Let's use trigonometry to find the height, see attached.

h = L - L cos θ

h = L (1- cos θ)

They indicate that the initial angle is tea = 48º and the length is L = 3.7 m, let's calculate.

h = 3.7 (1- cos 48)

h = 1.22 m

this is the maximum height of the movement.

Let's calculate the velocity.

$v= \sqrt{2 \ 9.8 \ 1.22}$

v = 4.89 m / s

In conclusion using the conservation of energy and trigonometry we can find the results for the questions about the movement of the acrobat are;

a) The maximum speed is v = 4.89 m / s

b) The maximum height is h = 1.22 m

Learn more here: brainly.com/question/13010190