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2 years ago

What is the current in the 60.0 resistor

Physics

2 answers:

Talja [164]2 years ago

8 0

Answer:

you must calculate it using the formula I=V/R

Artist 52 [7]2 years ago

7 0

Answer:

Option (c)

Explanation:

According to question,

R= 60 ohm

V=120 V

Current can be calculated as :

$I=\frac{V}{R}$

Where,

I is current

V is voltage

R is resistance

$I=\frac{120}{60} \\I=2 A$

Current is flowing across 60 ohm will be 2.0 A

Therefore, option c is correct

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an object traveling 200 feet per second slows to 50 feet per second in 5 seconds. Calculate the acceleration of the object

emmainna [20.7K]

Answer:

The acceleration of the object is $-30\ m/s^2$

Explanation:

Given:

Initial velocity of object $v_i$ = 200 feet/second

Final velocity of object $v_f$ = 50 feet/second

Time of travel = 5 seconds

To calculate acceleration of the object we will find the rate of change of velocity with respect to time.

So, acceleration $a$ is given by:

$a=\frac{v_f-v_i}{t}$

where $v_f$ represents final velocity, $v_i$ represents initial velocity and $t$ is time of travel.

Plugging in values to evaluate acceleration.

$a=\frac{50-200}{5}$

$a=\frac{-150}{5}$

$a=-30\ m/s^2$

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The time constant for RC circuit with the values of R1 and C1 is 5ms. What will be the time constant for a new RC circuit with t

lions [1.4K]

Answer:

d. 25 ms

Explanation:

In a RC circuit we call time constant to the product of the resistance times the capacitance, which represents the time when the charge reaches to the 63% of the final value, as follows:

$\tau_{1} = R_{1} *C_{1} = 5 ms (1)$

If we have a new circuit with new values for R and C, the time constant will be defined in the same way, as follows:

$\tau_{2} =10* R_{1} *0.5*C_{1} = 5*(R_{1}* C_{1}) = 5* \tau_{1} = 5* 5 ms = 25 ms (2)$

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