Answer:
4
Explanation:
<em>The number of progeny expected to display the dominant phenotype for both the A and B genes should be 4.</em>
<u>A test cross usually involves crossing an individual whose zygosity is in doubt with an individual that is recessive for both alleles so as to ascertain the zygosity of the former.</u> Hence, for a test cross involving AaBb:
AaBb x aabb
Progeny:
4 AaBb
4 Aabb
4 aaBb
4 aabb
<em>Therefore, the number of progeny expected to display the dominant phenotype for both the A and B genes is 4.</em>
Answer:
Free-living flatworms ingest food
Explanation:
Answer:
48 amino acids
Explanation:
The wild type gene codes for a protein with 100 amino acids. One amino acid is encoded by one triplet code of the gene. This means that the wild type gene has a total 100 triplets or 300 nucleotides to code for a protein of 100 amino acid. Mutation in this protein has introduced the code "UAA" at the 49th codon. The code "UAA" is a stop codon. Therefore, the mRNA transcribed from the mutant allele would code for a protein having 48 amino acids as the protein synthesis will be stopped once the stop codon at the 49th position is read.
Producers are called producers because when they take in carbon dioxide and water, and they produce glucose and oxygen. Animals need oxygen to survive and producers are the reason that all of the animals on earth haven't used up all the oxygen in the atmosphere. We need producers to survive, otherwise the Earth would be carbon dioxide rich and we humans couldn't breath it.