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2 years ago

Solve the inequality below for z . 5 − 8 ≥ z + 4

Mathematics

2 answers:

AnnyKZ [126]2 years ago

8 0

Answer:

$5 - 8 \geqslant z + 4 \\ - 3 \geqslant z + 4 \\ - 3 - 4 \geqslant z \\ \boxed{z \leqslant - 7}$

Tanya [424]2 years ago

7 0

Answer:

sorry man i need pont

Step-by-step explanation:

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Gilyann got a new puppy for her birthday. She went to the pet store to buy what she needed for the puppy: a food dish for $7.95,

Elina [12.6K]

Answer:

76.48

Step-by-step explanation:

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2 years ago

The bottom of the dais jewelry box of the rectangle with length of 5 3/8 inch in width of 3 and 1/4 in what is the area of the b

lesantik [10]

Answer:The area of the bottom of the jewelry box is 139.75 inch^2

Step-by-step explanation:

The area of a rectangle is expressed as

Area = Length × width

The length of the rectangular bottom of dais jewelry box is 5 3/8 inch. Converting to improper fraction, it becomes 43/8 inch.

The width of the rectangular bottom of dais jewelry box is 3 1/4 inch. Converting to improper fraction, it becomes 13/4 inch.

The area of the bottom of the jewelry box will be

43/8 × 13/4 = 559/32 = 139.75

7 0

2 years ago

Graph the linear equation y=-2/5x+2

Anvisha [2.4K]

Start at (0,2) and draw a dot. Then, go up 2 units, and right 5 times. Draw a dot. Now connect the 2 dots and extend the line.

Now, it's graphed! :)

4 0

2 years ago

The Weibull distribution is widely used in statistical problems relating to aging of solid insulating materials subjected to agi

fenix001 [56]

Answer:

Step-by-step explanation:

Given that

$\alpha =2.5$ , $\beta =220$

The weibull distribution with parameters $\alpha \ \ and \ \ \beta$

where $\alpha =0 \ \ , \beta =0$

$F(x,\alpha ,\beta) \left|\begin{array}{cc}\frac{\alpha }{\beta } x^{\alpha-1e^-(x/\beta)^\alpha &x\geq 0\\0&x$

Then,

$F(x,\alpha ,\beta )=\left|\begin{array}{cc}0&x$

A) The probability that a specimen's lifetime is at most 250 is

$P(X\leq 250)=F(250,2.7,220)\\\\=1-e^-^(250/220)^{2.7}\\\\=1-0.2436\\\\=0.7564$

The probability that the specimen's life time is more than 300 is

$P(X>300)=1-P(X\leq 300)\\\\=1-F(300;2.7,220)\\\\=1-(1-e^-^{(300/220)^{2.7}$

$=e^-^{(300/220)^{2.7}$

= 0.0992

b)The probability of the specimen's lifetime is between 100 and 250

$P(100$

c) The value such that exactly 50% of all specimens have lifetimes exceeding that value is

$P(X>x)=0.50\\\\1-P(X$

x = 192.07

7 0

2 years ago

Please help 50 points

ra1l [238]

Answer:

0 < y <= 6

Step-by-step explanation:

Given:

√(x² - 6x + 9)

if -3 <= x < 3

you can write (x² - 6x + 9)

as (x-3) * (x- 3) which is (x-3)²

so now you have √{(x-3)²}, which is the same as the absolute value of x-3. In mathematics it is written as:

| x - 3 |

So √(x² - 6x + 9) = | x - 3 |

See the graph in the attachment.

for -3 <= x < 3

you get the y values bigger then ( but not equal to) 0 and smaller then or equal to 6.

This is written as 0 < y <= 6

5 0

3 years ago

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