2 years ago

Figure PQRS is a rectangle.

Mathematics

1 answer:

il63 [147K]2 years ago

6 0

Answer:

4th option.

Step-by-step explanation:

PQ is not congruent to QR, instead it is PQ is perpendicular to QR.

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pentagon [3]

The answer is 2√19 I think

4 0

2 years ago

PLEASE HELP!!!!!! the sum of a number times 10 and 15 is at most -17

Brilliant_brown [7]

Let the number = x

Writing the equation you have:

10x + 15 <= -17

Solve for x

Subtract 15 from both sides:

10x <= -32

Divide both sides by 10:

X <= -32/10

Simplify:

X <= -16/5 as a fraction or -3.2 as a decimal

3 0

3 years ago

What the extreme point on the parabola

ki77a [65]

Answer:

Directrix

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Determine the commutators of the operators a and a+,where a = (x + ip)/2 ^1/2 and a+ = (x - ip)/ 2 ^1/2

Vsevolod [243]

Answer:

Given that:

$a = (\frac{x+ip}{2})^{\frac{1}{2}}$ and $a+= (\frac{x-ip}{2})^{\frac{1}{2}}$

if a , a+ commutator, it obeys $aa^+ = a^+a$

First find:

$aa^+ = (\frac{x+ip}{2})^{\frac{1}{2}} (\frac{x-ip}{2})^{\frac{1}{2}}$

= $(\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}=(\frac{(x)^2+(p)^2}{4})^{\frac{1}{2}}$

Now;

$a^+a =(\frac{x-ip}{2})^{\frac{1}{2}} (\frac{x+ip}{2})^{\frac{1}{2}} = (\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}$

= $(\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}=(\frac{(x)^2+(p)^2}{4})^{\frac{1}{2}}$

therefore, $aa^+ = a^+a$ which implies the operators a and a+ are commutators.

7 0

2 years ago

Fran has 7 sheets of paper for a colouring project. If she only uses 1/3 of a sheet of paper per drawing how many drawings can s

Sav [38]

So we can make an equation for this, being 7=1/3x, as that effectively says she can make 3 drawings per page.

Knowing this, we can multiply it by 3 to get x=21 (since if she can draw 3 drawings per page, we can imagine that if each drawing took a page she would need 3 times the pieces of paper), therefore she can make 21 drawings.

8 0

2 years ago